Problem Description
source: https://uva.onlinejudge.org/external/4/494.html
Everybody sit down in a circle. Ok. Listen to me carefully.
“Woooooo, you scwewy wabbit!”
Now, could someone tell me how many words I just said?
Input
Input to your program will consist of a series of lines, each line containing multiple words (at least one). A “word” is defined as a consecutive sequence of letters (upper and/or lower case).
Output
Your program should output a word count for each line of input. Each word count should be printed on a separate line.
Sample Input
Meep Meep!
I tot I taw a putty tat.
I did! I did! I did taw a putty tat.
Shsssssssssh ... I am hunting wabbits. Heh Heh Heh Heh ...
Sample Output
2
7
10
9
Solution:
source: https://uva.onlinejudge.org/external/4/494.html
Everybody sit down in a circle. Ok. Listen to me carefully.
“Woooooo, you scwewy wabbit!”
Now, could someone tell me how many words I just said?
Input
Input to your program will consist of a series of lines, each line containing multiple words (at least one). A “word” is defined as a consecutive sequence of letters (upper and/or lower case).
Output
Your program should output a word count for each line of input. Each word count should be printed on a separate line.
Sample Input
Meep Meep!
I tot I taw a putty tat.
I did! I did! I did taw a putty tat.
Shsssssssssh ... I am hunting wabbits. Heh Heh Heh Heh ...
Sample Output
2
7
10
9
Solution:
#include<stdio.h> #define max 100000 int main() { int i, count,start; char ch[max]; while(gets(ch)) { count=0; start=0; for(i=0;ch[i]!='\0';i++) { if(((ch[i]>='a' && ch[i]<='z') || ( ch[i]>='A' && ch[i]<='Z'))) start=1; else { if(start) { count++; start=0; } } } if(ch[i]=='\0' && start==1) count++; printf("%d\n",count); } return 0; }
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